satisfies? produces strange code when the protocol is not in the fast-path list

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Andrea Richiardi
November 2, 2018, 5:40 AM

Hello! Was reading up old Lisa tickets and stumbled upon this one. What does it mean in practical terms (sorry not really know what fast path is) and how could one reproduce it? I am using satisfy? here and there and this kinda scared me

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David Nolen

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David Nolen

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Minor
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